Question

The equation of tangent for curve y= 4xe^x at origin will be

Answer 1

Given: The curve y = 4xe^x.

To find: The equation of tangent for curve y = 4xe^x at origin?

Solution:

• Now we have given the curve :

               y= 4xe^x

• The equation of tangent on origin, that is (0,0) will be:

              dy / dx = 4e^x + 4xe^x

• Now dy/dx at (0,0) will be:

              dy / dx = 4e^0 + 4(0)e^0

              dy / dx = 4

• So the equation of tangent is:

              y - 0 = 4(x - 0)

              y = 4x

Answer:

           So the equation of tangent for curve y= 4xe^x at origin is y = 4x.

Answer 2

Step-by-step explanation:

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