The equation of tangent
line at the given of the
parameter will be
x=root t, y = 2t at t = 4
y = -8 (x-1)
y = 8 (x-1)
y = 8 (x+1)
y = -8 (x+1)
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How do you find an equation of the tangent line to the curve X = 2sin(2t), Y = 2sin(t), where the point corresponding to the value of parameter t = pi/6?
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4 Answers

Angad Kapoor, Math lover
Answered March 29, 2019
y(t)=2sin(t)y(t)=2sin(t)
x(t)=2sin(2t)x(t)=2sin(2t)
Let these two functions be together known as f(t)f(t)
∴f′(t)=y′(t)x′(t)∴f′(t)=y′(t)x′(t)
f′(t)=2cos(t)4cos(2t)f′(t)=2cos(t)4cos(2t)
f′(t)=cos(t)2cos(2t)f′(t)=cos(t)2cos(2t)
∴f′(π6)=cos(π6)2cos(π
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