Question

The equation of tangent to the curve y=x^+4x+1 at (-1,-3)is​

Answer 1

Step-by-step explanation:

y = x^2 + 4x +1

y' = 2x +4

point satisfying

y' = -2+4

y' = 2

EQ. of tangent will be

[y -(-1)] = y' [ x -(-3)]

y+1 = 2*(x+3)

y+1=2x+6

2x -y +5 =0