Question

the equation of tangent to the curve y=x²+4x+1 at (-1,2) is ?

Answer 1

$\frac{dy}{dx} = 2x + 4 \\ so \: slope \: at \: point \: ( - 1 \: 2) \\ = 2 \\ \\ now \: equation \: of \: tangent \: at \: given \: point \: i \\ \frac{y - 2}{x - 1} = 2 \\ y - 2 = 2x - 2 \\ 2x - y = 0$
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