Question

The equation of the chord of the circle x2+y2−6x+8y=0 which is bisected at the point (5,−3), is

Answer 1

\left[x \right] = \left[ \frac{x2}{6}+\frac{4\,y}{3}+\frac{y2}{6}\right][x]=[​6​​x2​​+​3​​4y​​+​6​​y2​​]. equation of the chord of the circle