Question

The equation of the circle having centre (1, - 2) and
passing through the point of intersection of lines
3 x + y = 14, 2x + 5y = 18 is
[MP PET 1990)
(a)
x2 + y2 - 2x + 4y - 20 = 0
(b) x2 + y2 - 2x - 4y -20 = 0
W
(c) x² + y² + 2x - 4y – 20 = 0
(d) x² + y2 + 2x + 4y - 20 = 0​

Answer 1

Answer:

a

Step-by-step explanation:

(x-1)^2+(y+2)^2=r2

solve for r by substituting point of intersection (4,2) r^2=25