Question

The equation of the circle passing
through the points (o, o), (o, b) and (a,b) is
(a) x2 + y2 + ax + by = 0
(b) x2 + y2 - ax + by = 0
(C) x2 + y2 - ax – by = 0
(d) x2 + y2 + ax – by = 0​

PLEASE ANSWER IT

Answer 1

Answer:

Let the equation of the required circle be 

(x−h)2+(y−k)2=r2

Since the circle passes through (0,0)

(0−h)2+(0−k)2=r2

⇒h2+k2=r2

So, the equation of the circle becomes 

(x−h)2+(y−k) 2=h2+k2

Given that the circle makes intercepts a and b on the coordinate axes. 

This means that the circle passes through points (a,0) and (0,b).

Therefore, (a−h)2+(0−k)2=h2+k2       ...(1)

(0−h)2+(b−k)2 =h2+k2     ...(2)

From equation (1) we obtain

a2−2ah+h2+k2=h2+k2

⇒a2−2ah=0

⇒a(a−2h)=

hope this helps you