The equation of the circle which passes through the origin has centre on the line x+y=
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Answer:
e will learn how to find the equation of a circle passes through the origin and centre lies on x-axis.
The equation of a circle with centre at (h, k) and radius equal to a, is (x - h)2 + (y - k)2 = a2.
When the circle passes through the origin and centre lies on x-axis i.e., h = a and k = 0.
Then the equation (x - h)2 + (y - k)2 = a2 becomes (x - a)2 + y2 = a2
Circle Passes through the Origin and Centre Lies on x-axis
Circle Passes through the Origin and Centre Lies on x-axis
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If a circle passes through the origin and centre lies on x-axis then the abscissa will be equal to the radius of the circle and the y co-ordinate of the centre will be zero. Hence, the equation of the circle will be of the form:
(x - a)2 + y2 = a2
⇒ x2 + y2 - 2ax = 0
Step-by-step explanation: