English, asked by 83828nitesh35353, 10 months ago

The equation of the circle whose centre is (1, -3) and which touches the line 2x - y -4 = 0 1
(a) 5x2 + 5y2 - 10x + 30y +49 = 0
(b) 5x2 + 5y + 10x - 30y +49 = 0
(C) 5x2 + 5y2 - 10x + 30y - 49 = 0
(d) None of these​

Answers

Answered by Anonymous
0

Explanation:

The equation of the circle whose centre is (1, -3) and which touches the line 2x - y -4 = 0 1

(a) 5x2 + 5y2 - 10x + 30y +49 = 0

(b) 5x2 + 5y + 10x - 30y +49 = 0

(C) 5x2 + 5y2 - 10x + 30y - 49 = 0

(d) None of these✔️✔️✔️✔️✔️

Answered by Anonymous
0

Explanation:

The equation of the circle whose centre is (1, -3) and which touches the line 2x - y -4 = 0 1

(a) 5x2 + 5y2 - 10x + 30y +49 = 0

(b) 5x2 + 5y + 10x - 30y +49 = 0

(C) 5x2 + 5y2 - 10x + 30y - 49 = 0

(d) None of these✔️✔️

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