Question

The equation of the circle with (1, 1) as centre and which cuts a chord of length 4V 2 units on the line x+y+1=Ois​

Answer 1

Answer:

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Step-by-step explanation:

Given,

4x−3y+2=0

(3,−2)

Length of perpendicular,

=42+(−3)24×3−3×(−2)+2

=520=4

Now, the circle cuts the intercept of length 6 at a distance of 3 on each side

Hence radius of circle is,

52+32=34

Hence the equation of circle is,

(x−3)2+(y+2)2=34

x2−6x+y2+4y−21=0

Answer 2

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