Question

The equation of the circle with (- 1, 2) and (4, 6) as the end points of a diameter​

Answer 1

Answer:

We know that the equation of the circle described on the line segment joining

(x

1

,y

1

) and (x

2

,y

2

) as a diameter is (x−x

1

)(x−x

2

)+(y−y

1

)(y−y

2

)=0.

Here, x

1

=−1,x

2

=4,y

1

=2,y

2

=−3.

So, the equation of the required circle is :

(x+1)(x−4)+(y−2)(y+3)=0

or, x

2

+y

2

−3x+y−10=0

Step-by-step explanation:

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