Question

the equation of the circle with center (4,1) and having 3x+4y-1 =0 as tangent​

Answer 1

Hey dude

ANSWERGiven, 3x+4y−1=0 is a tangent to a circle with centre (4,1) then r is perpendicular distance of (4,1) from 3x+4y−1=0.∴r=∣∣∣∣∣512+4−1∣∣∣∣∣∴r=∣∣∣∣∣515∣∣∣∣∣=3So, equation of circle having centre at (4,1) and radius 3 is (x−4)2+(y−1)2=9⇒ x2+y2−8x−2y+8=0

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