Question

The equation of the circle with centre (-1 0) and radius sqrt(7) is-

Answer 1

Answer:

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Step-by-step explanation:

$so \: now \: \\ here \: for \: a \ certain \: circle \\ coordinates \: of \: centre \: (h,k) = ( - 1,0) \\ also \: radius(r) = \sqrt{7} \: units$

$so \: now \: using \: \\ centre \: radius \: equation \: of \: circle \\ we \: get \\ (x - h) {}^{2} + (y - k) {}^{2} = r {}^{2} \\ (x - ( - 1)) {}^{2} + (y - 0) {}^{2} = ( \sqrt{7} )^{2} \\ (x + 1) {}^{2} + y {}^{2} = 7 \\ x {}^{2} + 2x + y {}^{2} + 1 - 7 = 0 \\ ie \: \: x {}^{2} + y {}^{2} + 2x - 6 = 0$

$hence \: \: The \: equation \: of \: the \: circle \: with \: centre \: (-1,0) \: and \: radius \: \sqrt{7} is \: \\ x {}^{2} + y {}^{2} + 2x - 6 = 0 \\ so \: hence \: option \: (C) \: is \: ryt$