Question

The equation of the circle with centre (3,-2) and radius 3 is
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Answer 1

The eqn. of a circle with centre (h,k) and radius r is given by, (x−h)2+(y−k)2=r2

Answer 2

Step-by-step explanation:

The equation of the circle with centre (3,-2) and radius 3 is—

➡️ According to distance formula—

➡️ distance=

$\sqrt{(x2 - x1) { }^ {2} } + \sqrt{(y2 - y1)}$

here—

A (x,y)

B (3,-2)

SO,,,⬇️. ⬇️. ⬇️. ⬇️. ⬇️.

$\sqrt{(3 - x) { }^{2} } + \sqrt{( - 2 - y) {}^{2} } = 3$

and from this you can see the answer on the above photo ⬆️ ⬆️ ⬆️ ⬆️ ⬆️

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