Question

The equation of the circle with centre (3,2) and the power of (1,-2) w.r.t the circle 221xy as radius is

Answer 1

$\huge{\dag} \: {\underline{\boxed{\sf{\purple{ ANSWER \ :- }}}}}$

$radius = \sqrt{g^{2} + f {}^{2} - c}$

$radius = \sqrt{1 + 4 - 1} \\ radius = 2$

$(x - 3)^{2} + (y - 2) ^{2} = k$

$(x = 1) \\ (y = - 2)$

$(1 - 3)^{2} + ( - 2 - 2) ^{2} = k \\ ( - 2) ^{2} + { (- 4)}^{2} = k \\k = 20$

${x}^{2} + {y}^{2} - 6x - 4y + 13 = 20 \\ {x}^{2} + {y}^{2} - 6x - 4y - 7 = 0$