Question

The equation of the curve which passes through the point (1, 3) and has the slope 4x-3 at any point (x, y) is

Answer 1

Answer:

y = 2x^2 - 3x + 4

Step-by-step explanation:

dy/dx = 4x - 3

dy = (4x-3)dx

Integrating,

y = 2x^2 - 3x + C

Putting values 1,3

3 = 2 - 3 + C

C = 4

So equation

y = 2x^2 - 3x + 4

If helpful mark as brainliest