Question

The equation of the diagonal AC of a square ABCD is 3x + 4y + 12 = 0. Find the equation of BD, where D is (2, -3). (a) 4.x - 3y - 8 = 0 (b) 4.x - 3y - 17 = 0 (c) 4x - 3y + 17 = 0 (d) 4x + 3y - 17 = 0​

Answer 1

Answer:

Correct Answer - B The equation of diagonal AC is 3 x + 4 y + 12 = 0 3x+4y+12=0 It slope = − 3 4 =-34 Slope of the other diagonal B D = 1 − 3 4 = 4 3 BD=1-34=43. BD passes though ( 2 , − 3 ) (2,-3) ∴ 4 3 = y − ( − 3 ) x − 2 ∴43=y-(-3)x-2 ∴ y + 3 = 4 3 ( x − 2 ) ∴y+3=43(x-2) 4 x − 3 y − 17 = 0 4x-3y-17=0.Read more on Sarthaks.com - https://www.sarthaks.com/1136079/the-equation-of-the-diagonal-ac-of-a-square-abcd-is-3x-4y-12-0-find-the-equation-of-bd-where-d-is