Math, asked by hamidraza0785, 10 hours ago

the equation of the family of circle passing through origin​

Answers

Answered by DarkenedSky
533

The equation of a circle with centre at (h, k) and radius equal to a, is  \sf{(x - h)^{2}  + (y - k)^{2}  = a ^{2} }

When the centre of the circle coincides with the origin i.e.,  \sf \: {a^{2}  = h^{2}   + k^{2} }

Answered by limvito
11

Answer:

The equation of a circle with centre at (h, k) and radius equal to a, is (x - h)2 + (y - k)2 = a2. ... When the centre of the circle coincides with the origin i.e., a2 = h2 + k2. Let O be the origin and C(h, k) be the centre of the circle.

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