Math, asked by PallabiBera58, 7 months ago

the equation of the hyperabola whose asymptotes are the straight lines3x-4y+7=0and4x+3y+1=0 and which passes through the origin is....
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Answers

Answered by pallabibera48
1

combined equation of asymptotes is (3x4y+7)(4c+3y+1)=0

the equation of the hyperbola is (3x-4y+7)(4x+3y+1)+k=0 and it pass through the origin (0,0)

or,7×1+k=0

or,k=-7

the hyperbola is 12x^2-7xy-12y^2+31x+17y=0

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