Question

The equation of the line in vector form passing through the point (-1 3 5) and parallel to line (x-3)/(2)=(y-4)/(3) z=2. is​

Answer 1

Step-by-step explanation:

Given  

The equation of the line in vector form passing through the point (-1 3 5) and parallel to line (x-3)/(2)=(y-4)/(3) z=2. is  

• Now equation of line passing through a point with position vector a and parallel to vector b is given by r = a + λ b

• Point is (-1, 3, 5)
• Now vector a = - I + 3j + 5k
• It is parallel to line x – 3 / 2 = y – 4 / 3 z = 2
• Therefore z component of equation is 0
• So line will be x – 3 / 2 = y – 4 / 3 = z – 2 / 0
• Now b = 2i + 3j + 0k
•             = 2i + 3j
• Therefore equation of the line is r = (- I + 3j + 5k) + λ(2i + 3j)

Reference link will be

https://brainly.in/question/10479704