Question

The equation of the line is 3y + 2x = 12. What is the slope of the line perpendicular to this equation?

Answer 1

3y + 2x = 12

To find the slope of this equation, we must turn this into slope-intercept form. Slope-intercept form is very simply : y = mx + b ; where m = slope, b = y-intercept.

Our first step should be to subtract 2x from both sides.

3y + 2x - 2x = 12 - 2x

Simplify.

3y = -2x + 12

Then, divide both sides by 3 so that we could get y by itself.

3y ÷ 3 = (-2x + 12) ÷ 3

Simplify.

$\text{y} = -\dfrac{2}{3}\text{x} + 4$

So, our slope is $\bold{-\dfrac{2}{3}}$

Answer 2

Answer:

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