Question

The equation of the line passing parralel to the straight line 3x+4y-7=0 and passing through the point (12) is

Answer 1

Any line parallel to... 3x+4y-7=0 is

3x+4y = k

where k is any constant.

since line 3x+4y = k is passes through (1 2) so..

3.1+4.2=k

k=11

so required line...

3x+4y=11