Math, asked by langlenchanu22, 6 months ago

The
equation of the line passing through
(1, 2) and perpendicular to x+y + 7= 0 is ?​

Answers

Answered by banudsharmila
0

Answer:

(x,y)=1,2

x+y+7=0

ax+by+c=0

a=1 b=2 c=7

perpendicular distance

d=modulus of [ax+by+c/roota^2+b^2]

= modulus of [1+1+7/root 1^2+root1^2]

=modulus of [9/root2]

d=9/root 2

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