Question

The equation of the line passing through (1947,1957)and (2017,2018) is...

Answer 1

first of all find slope joining by (1947, 1957) and ( 2017, 2018)

e.g slope = ( 2018 -1957)/( 2017-1947)
= 61/70

now, equation of line ,

( y -1957) = 61/70( x -1947)

70( y -1957) = 61( x-1947)

70y -61x = 61× 1947 - 70× 1957

61x - 70y = 18223

Answer 2

LET POINTS BE A(1947,1957)AND B(2017,2018)
Slope of AB=2018-1957/2017-1947=61/70
Equation of AB=(y-1957)=61/70(x-1947)
                    70(y-1957)=61(x-1947)
                   70y-70*1957=61x-61*1947
                   70y-61x=-118767+136990
                    -61x+70y=18223
                   -61x+70y-18223=0
                    61x-70y+18223=0