Question

The equation of the line passing through (2,3) and perpendicular to the line joining (-5,6) and (-6,5) is​

Answer 1

Answer:

slope on 1st line *slope on 2nd line= -1 [m₁*m₂= -1]

slope on 1st line(m₁) =y₂ -y₁/x₂ - x₁

                          =5-6/ -6-(-5)

                           = -1/ -1

                           =1

m₁ = 1

m₂= -1/1= -1

EQUATION IS:

y-y₁=m(x-x₁)

y₁=3 ; x₁=2

y-3= -1(x-2)

y-3= - x+2

y+x=5