Question

The equation of the line passing through (- 4, 3, 1), parallel to the plane x + 2y-z-5=0 and intersecting the line is :

Answer 1

Answer:

x + 2y - z = 1

Step-by-step explanation:

Given The equation of the line passing through (- 4, 3, 1), parallel to the plane x + 2y-z-5=0 and intersecting the line is :

Given equation is x + 2y - z = 5

Given from the equation normal vector of the plane is (1, 2, - 1)

general equation of the plane is

(x - xo, y - yo, z - zo) = 0

So we get

(1, 2, -1 )(x + 4, y - 3, z - 1) = 0

1(x + 4) + 2(y - 3) - 1(z - 1) = 0

x + 4 + 2y - 6 - z + 1 = 0

x + 2y - z - 1 = 0

x + 2y - z = 1

Answer 2

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Step-by-step explanation: