Question

the equation of the line passing through the point (1,-1,1),(3,2,4) and parallel to the y-axis is​

Answer 1

Step-by-step explanation:

a(x -1) + b(y -2) + c(z + 3) = 0 … … ..(1). Since it also passes through the point (2, -2, 1) therefore, a(2–1) + b(-2–2) + c(1+3) = 0 or a -4b + 4c = 0 …. … ..(2) . Further the plane (1) is || to x-axis whose drs are {1, 0, 0} therefore,we must have ; a.1 + b.0 + c.0 = 0 ==> a = 0. Now from (2), it gives, b = c =(k) (say) . Hence the required equation (1) becomes; k(y-2) + k(z + 3) = 0 or y+z + 3 = 0.