The equation of the line passing through the point (4, 5) with slope 2 is
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Use the slope −2 and the point (−4,−5) to find the y-intercept.
y=mx+b
⇒−5=(−2×−4)+b
⇒−5=8+b
⇒b=−13
Write the equation in slope intercept form as:
y=mx+b
⇒y=(−2)x−13
Hence, the equation of the line is y=−2x−13.
❥︎Hope it helps u mate
❥︎Sanuhere
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