Question

The equation of the line passing
through the point of intersection of the
lines 2x + y - 4 = 0, x - 3y + 5 = 0
and lying at a distance of 5 units
from the origin, is​

Answer 1

Answer:

2x+y-4=0-------------1

x-3y+5=0-------------2

by multiplying by 2 in equation no 2 we get:

2x-6y+10=0---------------2

2x+y-4=0----------------1

________

-5y=-6

5y=6

so y = 6/5

and x=-5+3y

x=-5+3×6/5

x=-5+18/5

x=-1.4

Answer 2

Answer:

✡️ QUESTION ✡️

➡️ The equation of the line passing through the point of intersection of the lines 2x + y - 4 = 0, x - 3y + 5 = 0 and lying at a distance of 5 units from the origin.

✡️ SOLUTION ✡️

2x + y - 4 = 0 .......(1)

x - 3y + 5 = 0 .......(2)

To eliminate y we multiply (1) by 3 ans (2) by 1 we get,

6x+3y-12 = 0

x - 3y +5 = 0

(-) (+) (-)

----------------------

7x 7 = 0

=> 7x = 7

=> x = 7/7

=> x = 1

Putting the value of x=1 in the equation

no (1) we get,

=> 6x+3y-12 = 0

=> 6(1)+3y-12=0

=> 3y = 12-6

=> y = 6/3

=> y = 2

Hence, the value of x = 1 and y = 2

Step-by-step explanation:

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