Question

the equation of the line perpendicular to the line 2x+3y-4=0 and passing through the origin​

Answer 1

Answer:

2x+3y−9=0

⇒ 3y=−2x+4

⇒ y=

3

−2

x+

3

4

Slope =m, =

3

−2

Slope of the perpendicular to m

1

⇒m

1

×m

2

=−1

m

2

=

m

1

1

=

2

3

m

2

=3/2

y=m+c ⇒ y=

2

3

x+c

it passes through original ⇒ 0=

2

3

(0)+c ⇒c=0

∴ y=

2

3

x⇒ 3x−2y=0

∴ The required equation is 3x−2y=0