Question

The equation of the line perpendicular to the line perpendicular to the line ax+by+c=0 and passing through the point (a,b) is

Answer 1

Answer:

Step-by-step explanation:

given line is : ax+by+c=0.

Slope of the line is given by(m1)=-coefficient of x/coefficient of y

= -a/b

Now, the slope of line perpendicular to the given line is (m2)= m1*m2= -1

=-a/b*m2= -1

= m2= b/a

Then the equation of line having slope b/a and passing through the point (a,b) is y-y1=m2(x-x1)

:y-b=b/a(x-a)

ay-ab-x+a= 0 is the required equation.