Question

The equation of the line perpendicular to
the line
x
2y = 7
-
and passing through the point of
intersection of the lines
2 x + 3y = 1
and
3 x + 4y = 6,
is​

Answer 1

Answer : 2x + 5y + 17=0

Step-by-step explanation:

Let the equation of line, which is perpendicular to 5x-2y=7 is <br>

<br> The point of intersection of given lines is (14,-9) <br> Since, Eq. (i) is passing through the point (14,-9) <br>

<br>

<br> Hence, Eq. becomes 2x + 5y + 17=0

Answer 2

Answer : 2x + 5y + 17=0

Step-by-step explanation:

Let the equation of line, which is perpendicular to 5x-2y=7 is <br>

<br> The point of intersection of given lines is (14,-9) <br> Since, Eq. (i) is passing through the point (14,-9) <br>

<br>

<br> Hence, Eq. becomes 2x + 5y + 17=0