Question

The equation of the line through
the points (3, 2) and (-2, 1 is​

Answer 1

Answer:

Equation of line through (3,2) & (−1,3) is 

∣∣∣∣∣∣x−3−1−3y−23−2∣∣∣∣∣∣=0

⇒∣∣∣∣∣∣x−3−4y−21∣∣∣∣∣∣=0

x−3+4(y−2)=0

⇒x+4y=11

Answer 2

Answer:

(3,-2),(3,1),(2,-2),(2,1)