Question

the equation of the line, when the portion od the intercepted between the axes is divuded by the point (2,3) in the ration of 3:2 is​

Answer 1

Answer:

The equation of the line, when the portion of it intercepted between the axes is divided by the point (2, 3) in the ratio of 3 : 2, is. Solution : Intercept form of line is xa+yb=1. ⇒a=5,b=5.

Answer 2

Answer:

Step-by-step explanation:

We have

given points are(2,−1)

ratio=m  1 :m  2  

=3:2  

Let the equation of line be

a x  +  by

​  

=1

The line meets the coordinates axes at

A(a, 0) and B(0,b) respectively.

m  1 :m  2

​  =  3:2

So

using section formula

(  m  1+m  2 m  1 x  2 +m  2 x 1 ,  m  1 +m  2 m 1 y  2 +m 2 y  1 )  

⇒(  3+2 3×0+2×a ,  3+2  3×b+2×0 )

⇒(  5 2a ,  6 3b  )

It is given that point (2, -1) divides

ratio 3:2

Now,  

5

2a

​ =2,    

5 3b

​ =−1

a=5,     b=  3 −5

Hence, the equation of line

5 x +  3 −5 y

​  

=1  ⇒ x−3y=5 x−3y−5=0.

Hence, this is the answer.