The equation of the line which passes through the point (-3, 8) and cuts off +ve intercepts on the axes whose sum is 7 is || 1) 3x-4y=12 2) 4x+3y=12 3) 3x+4y=12 4) 4x-3y =12
Answers
Answer:
2 option is correct i.e 4x+3y=12
Given : A line passes through the point (-3, 8) and cuts off +ve intercepts on the axes whose sum is 7
To Find : The Equation of the line
1) 3x-4y=12
2) 4x+3y=12
3) 3x+4y=12
4) 4x-3y =12
Solution:
Equation of the line
x/a + y/b = 1
a + b = 7 a ,b > 0
line passes through the point (-3, 8)
=> - 3/a + 8/b = 1
=> -3/a + 8/(7 - a) = 1
=> - 3(7 - a) + 8a = a(7 - a)
=> -21 + 3a + 8a = 7a - a²
=> a² + 4a - 21 = 0
=> (a + 7)(a - 3) = 0
=> a = - 7 , a = 3
as a > 0
a = 3
b = 4
x/3 + y/4 = 1
=> 4x + 3y = 12
4x + 3y = 12 is The equation of the line which passes through the point (-3, 8) and cuts off +ve intercepts on the axes whose sum is 7
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