Question

the equation of the line whose x-intercept is -5/7 and which is parallel to 3x+4y-7

Answer 1

From the equation
3x+4y-7=0
y = -3x/4 +7/4

m= -3/4
C= -5/7 ( given)
therefore
y=mx+C
y = -3/4x +-5/7
28y = -21x -20
21x+28y+20=0

Answer 2

Step-by-step explanation:

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