Math, asked by nimbalkarrajnandini, 2 months ago

The equation of the locus of a point equidistant from the point A(1.3) and B(-2.1) is
(a) 6x - 4y = 5
(b) 6x + 4y = 5
(c) 6x + 4y = 7
(d) 6x - 4y = 7

Answers

Answered by kkalicharan

0

Answer:

I don't know the answer friend sorroy for the answer

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