Question

The equation of the locus of the point (a sec theta + b tan theta , a tan theta + b sec theta )....
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Answer 1

The locus of the point (asecθ+btanθ,atanθ+bsecθ) is

A

x2+y2=a2+b2

B

x2+y2=a2−b2

C

x2−y2=a2+b2

D

x2−y2=a2−b2

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ANSWER

(x,y)=(asecθ+btanθ,atanθ+bsecθ)

Hence, x=asecθ+btanθ

x2=a2sec2θ+b2tan2θ+2absec