Question

the equation of the locus of the point it which moves equidistant form the the co-ordinate axis is​

Answer 1

Answer:

Let an arbitrary point be P(x,y).

Hence distance from x-axis is

d

x

=∣y∣ and distance of the point from y-axis is

d

y

=∣x∣

Now it is given that

d

y

=d

x

or

∣x∣=∣y∣

or

x=y and x=−y

Hence

x−y=0 and x+y=0

Therefore the combined equation will be

(x−y)(x+y)=0

x

2

−y

2

=0