Question

The equation of the normal to the curve y = sin x at (0,0) is​

Answer 1

Solution

Given  y=sinx

We have to find equation of normal at ( 0 , 0 )

Now Differentiate y = sinx W.r.t. x

→Dy/dx  = Cosx  = Cos0° = 1

The Slope  of normal ( m )  is -1/(dy/dx) = - 1

Formula of finding Equation of slope is

→ (y₂ - y₁) = m(x₂ - x₁)

So We have

→x₁ = 0 , x₂ = x , y₁ = 0 ,  y₂ = y and m = -1

By putting the value on equation we get

→( y - 0 ) = -1( x - 0 )

→y = -x

→x + y = 0

Answer

Equation of normal is x + y = 0