Question

The equation of the parabola with its vertex at the origin, axis on the y-axis and passing through the point (6, -3) is

Answer 1

Answer:

Step-by-step explanation:

In this question the value of vertex is (0,0);

Means h=0 and k=0;

Parabola passing through (6,-3) here x=6 and y=-3;

The standard form of parabola equation is

y=a(x-h)^2+k;

Putting the value of x, y, h and k in this equation

we get

-3=a(6-0)^2+0;

-3=36a;

a=-1/12;

The equation is y=(-1/12)x^2