The equation of the perpendicular bisector of line segment joining points A(4,5) and B(-2,3) is
Answers
Step-by-step explanation:
Since, the slope of the line AB= x 2 −x 1 y 2 −y 1 = 6−2−5−3 = 4−8 =−2 But slope of perpendicular bisector will be=− m1 = 21 Therefore, the equation of the liney+1= 21 (x−4)2y+2=x−4x−2y=6
Hope this will help you buddy...
Have a great day ahead ✌️
To find:
The equation of the perpendicular bisector of line segment joining the points A (4, 5) and B (- 2, 3)
Step-by-step explanation:
The equation of the line segment AB is
⇒ 3y - 15 = x - 4
⇒ x - 3y + 11 = 0
Let, the line perpendicular to the line segment AB be
3x + y = k ... ... (i)
The coordinates of the mid-point of AB are
i.e.,
i.e., (1, 4)
Here (i) no. line passes through the ppint (1, 4). Then
3 + 4 = k
⇒ k = 7
From (i), we get
3x + y = 7
Final answer: 3x + y = 7
The equation of the perpendicular bisector of line segment joining the points A (4, 5) and B (- 2, 3) is 3x + y = 7.
Read more on Brainly.in
a straight line is parallel to the line 3x-y-3=0 and 3x-y+5=0 and lies between them find equation of the line if it's di...
- https://brainly.in/question/12891227
Question No. 27 : Show that the equation 5x² - 6xy + y² = 0 represents a pair of straight lines. Find the straight line...
- https://brainly.in/question/3956094