Question

The equation of the perpendicular bisector of the line segment joining the points (2, 0) and (3, -1) is​

Answer 1

Answer:

x-y-3=0 is the equation of perpendicular bisected of line joining (2,0) and (3,-1)

Step-by-step explanation:

first find the slope of line joining the given two points i.e

m= (-1-0)/(3-2)= -1

then the slope of perpendicular line

= -(1/m)= 1 (product of slope two

perpendicular lines is

always -1)

but we have to find the equation perpendicular bisector. so the perpendicular line shouldbpass through the mid point is line joining given points.

so the mid point is ((3+2)/2, (0-1)/2)= (5/2, -1/2)

so the perpendicular bisector of the line passes through (5/2, -1/2) and it's slope is 1.

now the equation is

y-(-1/2)= 1 (x-5/2)

y+1/2= x-5/2

2y+1=2x-5

2x-2y-6= 0

x-y-3= 0 is the equation of perpendicular bisector of the line joining the given two points.