The equation of the radical axis of a coaxial system of circle whose limiting points are (2,-1) and (-3,2) is
5x + 3y - 4 = 0
5x + 3y + 4 = 0
5x – 3y + 4 = 0
3x - 5y + 4 = 0
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eqn of radial axis is given by s1−s2=0
s1=x2+y2+3x+4y−5=0
s2=x2+y2−5x+5y−6=0
∴s1−s2=0
⇒8x−y+1=0
slope=m=−1−8=8
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