Question

The equation of the sphere whose centre is (1,1,1) and which passes through (3,3,2), is kindly consider x2, y2, z2 as x square, y square, z square

Answer 1

Answer:

please make me brilliant then I well tell you answer

Answer 2

Given : sphere whose centre is (1,1,1) and which passes through (3,3,2)

To Find : Equation of sphere;

Solution:

Equation of sphere

(x - a)² + (y - b)² + (z - c)² = r²

(a , b , c) is center

a = 1 , b = 1 , c = 1

r = radius

=> (x - 1)² + (y - 1)² + (z - 1)² = r²

passes through (3,3,2)

=>(3 - 1)² + (3 - 1)² + (2 - 1)² = r²

=> 4 + 4 + 1 =  r²

=> 9 =  r²

Hence  (x - 1)² + (y - 1)² + (z - 1)² = 9 is the required equation of the sphere

Learn MorE:

Equation of the circle which is such that the lengths of the tangents ...

brainly.in/question/13068835

find the equation of circle which passed through origin and cuts off ...

brainly.in/question/2075668