Question

The equation of the straight road which is equidistant from two parallel straight roads represented by
6
x
+
4
y
−
5
=
0
and
3
x
+
2
y
+
4
=
0
is

Answer 1

Answer:

The equation of the straight road which is equidistant from two parallel straight roads represented by 6x+4y−5=0 and 3x+2y+4=0 is

A: 12x−8y+3=0

B: 8x−12y−3=0

C: 12x+8y+3=0

D: 8x+12y+3=0

Answer 2

Step-by-step explanation:

6x+4y-5=0 -----1

3x+2y+4=0 ----- 2

Both lines are parallel because of having same slope ie,-3/2

if the straight road is equidistant from both parallel straight roads

multiplying ----2 with 2

6x+4y-5=0

6x+4y+8=0

c=5

d=8

using this equation ax+by+(c+d/2)=0

we get 6x+4y+3/2=0

(6x+4y+3/2) *2

we get

12x+8y+3=0