Question

The equation of the tangent to the circle is x^2 + y^2 = 4 which are parallel to x+2y+3=0​

Answer 1

we know that

tengent = dy/dx

Given

x^2 + y^2 = 4

differentiating with respect to X

2ydy/dx = 2x

dy/dx = X/y

Equation of parallel line

X + 2y+ 3 = 0

differentiating with respect to X

2dy/dx = -1

dy/dx = -1/2

From above equation

x/y = -1/2 = dy/dx

equation of tangent

2x + y =0

Answer 2

Answer:

Here is your answer ll

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