Question

The equation of the tangent to the curve x ^ 2 = 4y at the point on the curve where x = - 2 is​

Answer 1

Step-by-step explanation:

The slope of the tangent line is given by the 1st derivative of the function.

x^2 = 4y

y = x^2 / 4

y' = x/2

for x = -2, the slope is -2/2 = -1

To get the equation of the tangent line, first solve the original equation for y when x = -2 (the tangent point)

Using the slope/intercept format, the equation is y = mx + b, where m is the slope and b is the y intercept. Plug in the values for m, x, and y, and solve for b

Answer 2

Answer:

for x = -2, the slope is -2/2 = -1

Step-by-step explanation:

The slope of the tangent line is given by the 1st derivative of the function.

x^2 = 4y

y = x^2 / 4

y' = x/2

for x = -2, the slope is -2/2 = -1

To get the equation of the tangent line, first solve the original equation for y when x = -2 (the tangent point)

Using the slope/intercept format, the equation is y = mx + b, where m is the slope and b is the y intercept. Plug in the values for m, x, and y, and solve for b