Question

the equation of the tangent to the curve y=e^2x at (0 1) is​

Answer 1

Answer:

3rd option

Step-by-step explanation:

Slope at (0,1) = dy/dx = 2 . e^2x

dy/dx = 2 e^0 = 2

Equation of tangent = > (y-1) = 2(x)

=> y-1 = 2x

Hope it helps

Please mark as brainliest

Answer 2

Answer:

Check it out . Hope it will help u !