Question

The equation of trajectory of a particle under ground to ground projection is given as y = 6x - 3x^2 (where x and y are in metre). The horizontal range of the particle will be?

Answer 1

Explanation:

i would suggest you to learn this modified equation of trajectory...

Answer 2

Concept Introduction: Projectile motion is a two dimensional motion.

Given:

We have been Given:

$y = 6x - 3 {x}^{2}$

To Find: The horizontal range of the particle will be?

Solution:

According to the problem, Equation of Trajectory is given by

$y = x \tan \alpha (1 - \frac{x}{r} )$

therefore, putting the above equation in the trajectory equation we get

$y = 6x(1 - \frac{x}{2} )$

Therefore on comparing it with the original equation it shows that range of the particle is

$r = 2m$

Final Answer: The Horizontal Range of the particle is

$2m$

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